Subscribe on YouTube

IB Chemistry | Year 2 (Senior) · Electron Sharing Reactions: Radicals · part 1/5

Radicals & Homolytic Fission Explained

Radicals & Homolytic Fission Explained

IB Chemistry Reactivity 3.3, electron sharing reactions: radicals and homolytic fission (part 1 of 5, for SL and HL). What a radical is, how homolytic fission makes two radicals, and why the reaction of a halogen needs UV light. Includes a six mark exam-style question solved step by step.

In this lesson

  1. 0:00 Intro
  2. 0:14 Exam question
  3. 0:35 Warm-up
  4. 1:07 What a radical is
  5. 2:25 Homolytic fission
  6. 3:27 UV light and initiation
  7. 4:20 Practice: write the equation
  8. 5:30 What earns the mark
  9. 6:09 Exam question solved
  10. 7:01 Recap
Answers to the practice questions at the end of the video
  1. CH₃ has 9 electrons and NO has 15: odd numbers, so each has an unpaired electron [1 each]. CH₄ has 10 and N₂ has 14, all paired.
  2. I₂ → 2I•, with UV light (or heat) above the arrow [1].
  3. Without UV light there is not enough energy to break the Cl–Cl bond [1], so no chlorine radicals form and the reaction cannot start [1].

Questions are original, in the style of the exam; marks are estimates.

New IB lessons every day. Subscribe to TheIBAxolotl so the next part shows up in your feed.