AxoPrep

Physics

A.2 Forces and momentum

How forces change motion through Newton's three laws, how to draw free-body diagrams, and how momentum, impulse and centripetal force explain collisions and circular paths. Study guide, 5 practice questions with markschemes and 8 flashcards. Free.

Newton's three laws · free-body diagrams · friction, tension, normal force, buoyancy, drag and Hooke's law · momentum, impulse and conservation · elastic and inelastic collisions and explosions · circular motion and centripetal force

Practise all 5 questions Study 8 flashcards

Study guide

Forces and Newton's laws

A force is a push or pull that can change an object's velocity or shape. Newton's laws tie forces to motion:

  1. First law. If the resultant force on a body is zero, its velocity does not change: it stays at rest or keeps moving in a straight line at constant speed. Balanced forces mean no acceleration, not no motion.
  2. Second law. The resultant force equals the rate of change of momentum, \(F = \frac{\Delta p}{\Delta t}\). For constant mass this becomes \(F = ma\).
  3. Third law. When body A pushes on body B, B pushes back on A with a force equal in size, opposite in direction and of the same type. The pair acts on different bodies, so the two forces never cancel each other.

Free-body diagrams

Draw the object as a dot or box and show only the forces acting on it, each as an arrow starting at the object. Common forces:

Resolve forces into perpendicular components, usually along and across a slope or horizontal and vertical.

Momentum and impulse

Linear momentum is \(p = mv\), a vector in kg m s\(^{-1}\). Impulse is the change in momentum, \(J = F\Delta t = \Delta p\), and equals the area under a force–time graph. Air bags and crumple zones increase the collision time, so the same change of momentum needs a smaller average force.

In a closed system with no external resultant force, total momentum is conserved. This holds in every collision and explosion.

Circular motion

An object moving in a circle at constant speed is still accelerating, because its direction changes. The acceleration points toward the centre:

\[a = \frac{v^2}{r} = \omega^2 r = \frac{4\pi^2 r}{T^2}\]

The centripetal force \(F = \frac{mv^2}{r}\) is not a new kind of force. It is the name for the resultant inward force, supplied by friction (a car on a bend), tension (a ball on a string), gravity (an orbit) or a normal force. Angular speed is \(\omega = \frac{2\pi}{T}\) and \(v = \omega r\).

Worked example 1: friction and Newton's second law

A \(25\ \text{kg}\) crate is pushed across a level floor with a horizontal force of \(120\ \text{N}\). The coefficient of kinetic friction is \(0.30\). Find the acceleration (\(g = 9.81\ \text{m s}^{-2}\)).

Worked example 2: a sticky collision

A \(2.0\ \text{kg}\) trolley at \(3.0\ \text{m s}^{-1}\) hits a stationary \(1.0\ \text{kg}\) trolley, and they move off together.

Common mistakes

Exam tips

Cheat sheet

EquationSymbolsUnits
\(F = ma\), \(F = \frac{\Delta p}{\Delta t}\)\(F\) resultant force, \(m\) mass, \(a\) accelerationN
\(W = mg\)\(g = 9.81\) N kg\(^{-1}\)N
\(F_f \le \mu_s N\), \(F_f = \mu_d N\)\(\mu\) friction coefficient, \(N\) normal forceN
\(F_H = -kx\)\(k\) spring constant, \(x\) extensionN
\(F_b = \rho V g\)\(\rho\) fluid density, \(V\) volume displacedN
\(F_d = 6\pi\eta r v\)\(\eta\) viscosity, \(r\) radius, \(v\) speedN
\(p = mv\)\(p\) momentumkg m s\(^{-1}\)
\(J = F\Delta t = \Delta p\)\(J\) impulseN s
\(a = \frac{v^2}{r} = \omega^2 r\)\(r\) radius, \(\omega\) angular speedm s\(^{-2}\)
\(F = \frac{mv^2}{r}\), \(v = \omega r\), \(\omega = \frac{2\pi}{T}\)\(T\) periodN, rad s\(^{-1}\)

Key definitions

Resultant force

The single force that has the same effect as all the forces acting on a body combined, found by vector addition.

Newton's third law pair

Two forces of equal size and opposite direction, of the same type, that two bodies exert on each other; they act on different bodies.

Linear momentum

The product of an object's mass and velocity; a vector measured in kg m s^-1.

Impulse

The product of a force and the time for which it acts, equal to the change in momentum it produces and to the area under a force–time graph.

Elastic collision

A collision in which total kinetic energy is the same before and after, as well as total momentum.

Inelastic collision

A collision in which some kinetic energy is transferred to other forms, although total momentum is still conserved.

Centripetal force

The resultant force directed toward the centre of a circular path that keeps an object moving in a circle.

Coefficient of friction

The ratio of the maximum friction force between two surfaces to the normal force pressing them together; it has no units.

Practice questions

SLPaper 1AStandard

Question 1

(a) [1]

A laptop rests on a desk. According to Newton's third law, which force forms a pair with the weight of the laptop?

  • A. The upward normal force of the desk on the laptop
  • B. The gravitational force of the laptop on the Earth
  • C. The downward push of the laptop on the desk
  • D. The gravitational force of the Earth on the desk
Markscheme
  • 1 B. Third-law pairs are the same type of force acting on two different bodies: Earth pulls laptop, laptop pulls Earth.
SLPaper 1AStandard

Question 2

(a) [1]

A ball of mass \(0.20\ \text{kg}\) moving at \(15\ \text{m s}^{-1}\) hits a wall at right angles and rebounds along the same line at \(10\ \text{m s}^{-1}\). What is the magnitude of the impulse on the ball?

  • A. \(1.0\ \text{N s}\)
  • B. \(3.0\ \text{N s}\)
  • C. \(5.0\ \text{N s}\)
  • D. \(50\ \text{N s}\)
Markscheme
  • 1 C. Velocity changes by \(15 + 10 = 25\ \text{m s}^{-1}\) because the direction reverses, so \(\Delta p = 0.20 \times 25 = 5.0\ \text{N s}\).
SLPaper 2Standard

Question 3

On a level, frictionless track, trolley P of mass \(1.50\ \text{kg}\) moves at \(2.40\ \text{m s}^{-1}\) towards trolley Q of mass \(0.90\ \text{kg}\), which is at rest. They collide and stick together.

(a) [2]

Calculate the speed of the two trolleys immediately after the collision.

Markscheme
  • 1 Momentum conserved: \(1.50 \times 2.40 = (1.50 + 0.90)v\)
  • 1 \(v = \frac{3.60}{2.40} = 1.50\ \text{m s}^{-1}\)
(b) [3]

Determine the kinetic energy transferred to other forms in the collision.

Markscheme
  • 1 Initial \(E_k = \frac{1}{2} \times 1.50 \times 2.40^2 = 4.32\ \text{J}\)
  • 1 Final \(E_k = \frac{1}{2} \times 2.40 \times 1.50^2 = 2.70\ \text{J}\)
  • 1 Energy transferred \(= 1.62\ \text{J}\)
(c) [1]

State, with a reason, whether the collision is elastic or inelastic.

Markscheme
  • 1 Inelastic, because total kinetic energy is not conserved (it decreases), even though momentum is conserved

Key facts

State Newton's second law in terms of momentum.

The resultant force equals the rate of change of momentum: \(F = \frac{\Delta p}{\Delta t}\) (which gives \(F = ma\) for constant mass).

What are the features of a Newton's third law pair?

Equal size, opposite direction, same type of force, acting on two different bodies.

Define impulse and give its unit.

Impulse \(= F\Delta t = \Delta p\), the change in momentum. Unit: N s (equivalent to kg m s\(^{-1}\)). It equals the area under a force–time graph.

When is linear momentum conserved?

When no external resultant force acts on the system.

Elastic vs inelastic collision?

Momentum is conserved in both. Kinetic energy is conserved only in an elastic collision.

Equation for centripetal force

\(F = \frac{mv^2}{r} = m\omega^2 r\), directed towards the centre of the circle.