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Mathematics: Applications and Interpretation

SL 4.3 Measures of central tendency and dispersion

Mean, median and mode, grouped-data estimates, range, IQR, variance and standard deviation, and how they react to transformations. Study guide, 3 practice questions with markschemes and 4 flashcards. Free.

Mean, median and mode · Grouped-data estimates and modal class · Range, IQR, variance and standard deviation · Effect of constant changes · Using technology for statistics

Practise all 3 questions Study 4 flashcards

Study guide

Measures of centre

Grouped data

When data are grouped, the exact values are lost, so the mean is an estimate. Replace each class by its mid-interval value and use the frequencies. The modal class is the class with the highest frequency (for equal widths).

Measures of spread

\[\sigma^2 = \frac{\sum f (x - \bar{x})^2}{\sum f}\]

In this course the standard deviation is found with technology, and it is the population version (\(\sigma_x\) on most calculators, not \(s_x\)).

Worked example

Waiting times (minutes):

Time \(t\)\(0 \le t < 10\)\(10 \le t < 20\)\(20 \le t < 30\)
Frequency4106

Midpoints 5, 15, 25. Estimated mean \(= \dfrac{4(5) + 10(15) + 6(25)}{20} = \dfrac{320}{20} = 16\) minutes. Entering midpoints and frequencies in the GDC gives \(\sigma = 7\) minutes (check: mean of squares \(= 305\), so \(\sigma^2 = 305 - 16^2 = 49\)). The modal class is \(10 \le t < 20\).

Effect of constant changes

If every value is changed in the same way:

ChangeMean, median, modeSD, IQR, rangeVariance
add \(c\)\(+ c\)unchangedunchanged
multiply by \(k\) (\(k>0\))\(\times k\)\(\times k\)\(\times k^2\)

For example, if every worker's wage rises by USD 20 a day, the mean wage rises by USD 20 and the standard deviation stays the same; a 5% pay rise multiplies both by 1.05.

Finding a missing value

If the mean of a set is known, use \(\sum x = n\bar{x}\) to find an unknown value or frequency. For example, if five numbers have mean 12 and four of them add to 47, the fifth is \(60 - 47 = 13\).

GDC tips

Common mistakes

Exam tips

Cheat sheet

Key definitions

Mean

The sum of the values divided by the number of values.

Median

The middle value when the data are arranged in order.

Mode

The value that occurs most often.

Modal class

The class interval with the highest frequency in grouped data.

Mid-interval value

The midpoint of a class, used to stand in for every value in that class.

Standard deviation

A measure of how spread out values are around the mean; the square root of the variance.

Variance

The mean of the squared deviations from the mean.

Practice questions

SLPaper 2Standard

Question 1

A librarian recorded the number of books read last month by 40 students.

Books012345
Frequency4912852
(a) [1]

Write down the mode.

Markscheme
  • 1 \(2\)
(b) [2]

Find the median.

Markscheme
  • 1 Identifies the 20th and 21st values (cumulative frequencies 4, 13, 25)
  • 1 \(2\)
(c) [2]

Find the mean.

Markscheme
  • 1 \(\frac{\sum fx}{40} = \frac{87}{40}\)
  • 1 \(2.175\) (2.18)
(d) [1]

Find the standard deviation.

Markscheme
  • 1 \(1.32\) (1.3207...)
SLPaper 2Standard

Question 2

The waiting times, \(t\) minutes, of 50 customers at a phone repair shop are shown.

Time (min)\(0 \le t < 5\)\(5 \le t < 10\)\(10 \le t < 15\)\(15 \le t < 20\)\(20 \le t < 30\)
Frequency6141893
(a) [1]

Write down the modal class.

Markscheme
  • 1 \(10 \le t < 15\)
(b) [3]

Calculate an estimate of the mean waiting time.

Markscheme
  • 1 Uses mid-interval values 2.5, 7.5, 12.5, 17.5, 25
  • 1 \(\frac{577.5}{50}\)
  • 1 \(11.55\) minutes (11.6)
(c) [1]

Explain why your answer to part (b) is only an estimate.

Markscheme
  • 1 The exact times are not known; each value is replaced by the midpoint of its class
SLPaper 1Challenging

Question 3

The daily wages of workers at a factory have mean EUR 45 and standard deviation EUR 6.

(a) [2]

Each worker receives a bonus of EUR 2 per day. Write down the new mean and standard deviation.

Markscheme
  • 1 Mean EUR 47
  • 1 Standard deviation EUR 6 (unchanged)
(b) [2]

Instead, every original wage is increased by 8% and then a EUR 2 bonus is added. Find the new mean and new standard deviation.

Markscheme
  • 1 Mean: \(45 \times 1.08 + 2 = 50.6\)
  • 1 Standard deviation: \(6 \times 1.08 = 6.48\)

Key facts

GDC tip for statistics from a frequency table

Put values in L1 and frequencies in L2, then run 1-Var Stats with FreqList set to L2. Forgetting the frequency list is a common error.

Effect on mean and SD of adding \(k\) to every value

Mean increases by \(k\); standard deviation (and variance) does not change.

Effect on mean and SD of multiplying every value by \(a\) (\(a > 0\))

Mean and standard deviation are both multiplied by \(a\); variance is multiplied by \(a^2\).

How do you estimate the mean from grouped data?

Multiply each class midpoint by its frequency, add the products and divide by the total frequency.