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Mathematics: Applications and Interpretation

SL 1.4 Financial applications: compound interest and depreciation

Compound interest with different compounding periods, depreciation, inflation and the GDC finance solver. Study guide, 3 practice questions with markschemes and 5 flashcards. Free.

Compound interest with various compounding periods · Annual depreciation · Calculator finance solver · Inflation and real value · Comparing options

Practise all 3 questions Study 5 flashcards

Study guide

Interest on interest

With compound interest, each period's interest is added to the balance and then earns interest itself. The balance therefore follows a geometric sequence. If the nominal annual rate is \(r\%\) and interest is added \(k\) times a year, the rate per period is \(\dfrac{r}{100k}\) and after \(n\) years there have been \(kn\) periods:

\[FV = PV \times \left(1 + \frac{r}{100k}\right)^{kn}\]

Common values of \(k\): 1 (annually), 2 (half-yearly), 4 (quarterly), 12 (monthly).

Worked example

Ana invests USD 8000 at a nominal 3.6% per year compounded monthly for 5 years.

\[FV = 8000\left(1 + \frac{3.6}{1200}\right)^{60} = 8000 \times 1.003^{60} \approx 9575.16\]

She earns about USD 1575.16 in interest. The same rate compounded annually would give \(8000 \times 1.036^{5} \approx 9547.48\): more frequent compounding earns slightly more.

Depreciation

Equipment and vehicles typically lose a fixed percentage of their value each year:

\[V_n = V_0\left(1 - \frac{r}{100}\right)^{n}\]

A van bought for USD 32 000 that depreciates by 18% a year is worth \(32\,000 \times 0.82^{4} \approx\) USD 14 467.90 after 4 years.

Using the finance solver (TVM)

Every GDC has a time-value-of-money solver. Enter all values except the unknown and solve for it.

FieldMeaning
Ntotal number of periods (\(kn\))
I%nominal annual rate (not divided by \(k\))
PVpresent value; money you pay out is negative
PMTregular payment (0 for a single investment)
FVfuture value; money you receive is positive
P/Y, C/Ypayments and compounding periods per year

The sign convention matters: an investment has PV negative and FV positive. If both have the same sign, the solver gives an error or nonsense.

Inflation and real value

Inflation reduces what money can buy. To compare across time, find the real value: divide a future amount by the inflation factor, for example USD 10 000 in 5 years with 3% inflation is worth about \(10\,000 \div 1.03^{5} \approx\) USD 8626 in today's money. Equivalently, a rough real interest rate is the nominal rate minus the inflation rate; use it in the solver when the question asks for this approach.

Comparing options

Typical questions compare two accounts, or ask for the rate or time needed to reach a target. Find the value of each option at the same date, or use the solver for N or I%. When solving for time, round N up to a whole number of periods and convert to years if asked.

Common mistakes

Exam tips

Cheat sheet

Key definitions

Compound interest

Interest added to the balance at the end of each period so that it earns further interest.

Nominal annual rate

The stated yearly interest rate before it is split across compounding periods.

Compounding period

The interval at which interest is calculated and added, for example monthly.

Depreciation

The loss in value of an asset over time, often modelled as a fixed percentage per year.

Present value (PV)

The value of money at the start of the time period being studied.

Future value (FV)

The value of an investment or loan after a stated number of periods.

Real value

An amount adjusted for inflation so it can be compared with today's purchasing power.

Practice questions

SLPaper 1Foundation

Question 1

Ana invests USD 8000 in an account paying a nominal annual interest rate of 4.2%, compounded monthly.

(a) [2]

Calculate the value of the investment after 6 years, to the nearest dollar.

Markscheme
  • 1 \(8000\left(1 + \frac{4.2}{100 \times 12}\right)^{12 \times 6}\) or correct finance-solver entries (\(N = 72\), \(I = 4.2\), \(PV = -8000\), \(P/Y = C/Y = 12\))
  • 1 USD 10 288
(b) [1]

Calculate the interest earned over the 6 years.

Markscheme
  • 1 USD 2288
SLPaper 2Challenging

Question 2

A delivery van is bought for EUR 32 500. Its value decreases by the same percentage each year. After 5 years it is worth EUR 14 800.

(a) [3]

Find the annual rate of depreciation, as a percentage correct to 3 significant figures.

Markscheme
  • 1 \(32\,500(1 - r)^5 = 14\,800\)
  • 1 \(1 - r = 0.8544\ldots\)
  • 1 \(14.6\%\)
(b) [3]

Find the number of complete years after purchase when the van's value first falls below EUR 8000.

Markscheme
  • 1 \(32\,500(0.85443)^n < 8000\), or a table of values
  • 1 Shows value after 8 years \(\approx 9232\) and after 9 years \(\approx 7888\)
  • 1 9 years
SLPaper 2Challenging

Question 3

Raj has USD 5000 to save. Bank A offers a nominal annual rate of 3.6% compounded quarterly. Bank B offers 3.65% compounded annually.

(a) [3]

Find the minimum number of whole years needed for the money to double in Bank A.

Markscheme
  • 1 \(5000\left(1 + \frac{3.6}{400}\right)^{4t} \ge 10\,000\) or finance solver with \(FV = 10\,000\)
  • 1 \(4t = 77.4\ldots\) quarters (or \(t = 19.3\ldots\))
  • 1 20 years
(b) [3]

Determine which bank gives the greater value after one year. Justify your answer.

Markscheme
  • 1 Bank A after 1 year: \(5000(1.009)^4 = 5182.44\) (or effective rate \(3.649\%\))
  • 1 Bank B after 1 year: \(5000 \times 1.0365 = 5182.50\)
  • 1 Bank B, by a very small amount (6 cents)

Key facts

Compound interest formula

\(FV = PV\left(1 + \frac{r}{100k}\right)^{kn}\), where \(r\) is the nominal annual rate (%), \(k\) compounding periods per year and \(n\) years.

Finance solver sign convention

Money paid out by you (e.g. an investment, PV) is negative; money you receive (FV) is positive. A loan you receive has PV positive and payments negative.

How do you model depreciation of \(r\%\) per year?

Value after \(n\) years \(= V_0\left(1 - \frac{r}{100}\right)^n\), a geometric sequence with ratio less than 1.

How do you find the real value of money after inflation?

Use the real interest rate: approximately (interest rate − inflation rate), or divide the future value by \((1 + i)^n\) where \(i\) is the inflation rate.

Does more frequent compounding always give more money at the same nominal rate?

Yes, but the gain is small. Compare offers by their effective annual rate, e.g. 3.6% quarterly is \(1.009^4 - 1 = 3.649\%\).