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Mathematics: Applications and Interpretation

SL 1.2 Arithmetic sequences and series

Sequences that grow by a fixed amount each step, their general term, their sums and linear-growth applications. Study guide, 3 practice questions with markschemes and 4 flashcards. Free.

Common difference and nth term · Sum of n terms · Sigma notation · Simple interest and linear growth applications · Modelling approximately arithmetic data

Practise all 3 questions Study 4 flashcards

Study guide

The idea

An arithmetic sequence changes by the same amount every step. Seats in rows that each have 3 more than the row before, a savings jar that gets USD 20 more every week, a taxi fare that rises by a fixed amount per kilometre: all of these are arithmetic. The fixed step is the common difference \(d\); it can be negative for a decreasing sequence.

The nth term

To reach term \(n\) you start at \(u_1\) and take \(n-1\) steps of size \(d\):

\[u_n = u_1 + (n-1)d\]

Two pieces of information (for example two terms) are enough to find \(u_1\) and \(d\): write two equations and solve them simultaneously, by hand or with the GDC's equation solver.

The sum of n terms

Pair the first term with the last, the second with the second-last, and so on: every pair has the same total. That gives

\[S_n = \frac{n}{2}(u_1 + u_n) = \frac{n}{2}\big(2u_1 + (n-1)d\big)\]

Use the first version when you know the last term, the second when you know \(d\).

Sigma notation

\(\displaystyle\sum_{k=1}^{10}(3k+2)\) means "substitute \(k = 1, 2, \dots, 10\) and add". The terms are \(5, 8, \dots, 32\), so the sum is \(\frac{10}{2}(5+32) = 185\). A GDC can evaluate sigma expressions directly, which is a good check.

Worked example

An outdoor theatre has 15 rows. The front row has 20 seats and each row has 3 more seats than the row in front of it.

Simple interest and linear models

Simple interest adds the same amount every year, so the balance forms an arithmetic sequence. With capital \(C\) and annual rate \(r\%\), the interest after \(n\) years is \(I = \dfrac{C r n}{100}\). Real data that rise by roughly the same amount each step can be modelled as arithmetic: estimate \(d\) from the average step, then say clearly that the model is an approximation.

GDC tips

Common mistakes

Exam tips

Cheat sheet

QuantityFormula
nth term\(u_n = u_1 + (n-1)d\)
Sum (last term known)\(S_n = \frac{n}{2}(u_1 + u_n)\)
Sum (d known)\(S_n = \frac{n}{2}(2u_1 + (n-1)d)\)
Common difference\(d = u_{n+1} - u_n\)
Simple interest\(I = \frac{Crn}{100}\)

Key definitions

Arithmetic sequence

A list of numbers in which each term is obtained by adding the same constant to the previous term.

Common difference

The constant d added each step; d = u(n+1) − u(n).

Arithmetic series

The sum of the terms of an arithmetic sequence.

Sigma notation

Compact notation Σ for adding the values of an expression as an index runs over a range of integers.

Simple interest

Interest calculated only on the original amount, so the same interest is added every period.

Linear model

A model in which a quantity increases or decreases by roughly the same amount each step.

Practice questions

SLPaper 1Foundation

Question 1

An outdoor theatre has 15 rows of seats. The first row has 18 seats and each row after that has 3 more seats than the row in front of it.

(a) [2]

Find the number of seats in the 15th row.

Markscheme
  • 1 \(u_{15} = 18 + 14 \times 3\)
  • 1 \(60\) seats
(b) [2]

Find the total number of seats in the theatre.

Markscheme
  • 1 \(S_{15} = \frac{15}{2}(18 + 60)\) or \(\frac{15}{2}(2 \times 18 + 14 \times 3)\)
  • 1 \(585\) seats
SLPaper 2Standard

Question 2

Mia starts saving for a trip. She saves USD 40 in week 1, and each week she saves USD 6 more than the week before.

(a) [2]

Find the amount she saves in week 20.

Markscheme
  • 1 \(40 + 19 \times 6\)
  • 1 USD 154
(b) [2]

Find the total she has saved after 20 weeks.

Markscheme
  • 1 \(\frac{20}{2}(40 + 154)\)
  • 1 USD 1940
(c) [3]

Find the first week in which her total savings exceed USD 5000.

Markscheme
  • 1 Sets up \(\frac{n}{2}(80 + 6(n-1)) > 5000\) (or \(=5000\))
  • 1 Solves with GDC: \(n = 35.1\ldots\), or shows \(S_{35} = 4970\) and \(S_{36} = 5220\)
  • 1 Week 36
SLPaper 2Challenging

Question 3

Leo follows a cycling plan in which the distance he rides each day increases by the same amount. On day 3 he rides 17.5 km and on day 10 he rides 45.5 km.

(a) [3]

Find the common difference and the distance he rides on day 1.

Markscheme
  • 1 Forms two equations: \(u_1 + 2d = 17.5\) and \(u_1 + 9d = 45.5\)
  • 1 \(d = 4\) km
  • 1 \(u_1 = 9.5\) km
(b) [3]

Find the first day on which he rides more than 100 km.

Markscheme
  • 1 \(9.5 + 4(n-1) > 100\)
  • 1 \(n > 23.6\ldots\) (or \(u_{23} = 97.5\), \(u_{24} = 101.5\))
  • 1 Day 24
(c) [2]

Find the total distance he rides in the first 24 days.

Markscheme
  • 1 \(\frac{24}{2}(9.5 + 101.5)\)
  • 1 \(1332\) km

Key facts

Formula for the \(n\)th term of an arithmetic sequence

\(u_n = u_1 + (n - 1)d\), where \(d\) is the common difference.

Two formulas for the sum of the first \(n\) terms of an arithmetic sequence

\(S_n = \frac{n}{2}\big(2u_1 + (n-1)d\big)\) or \(S_n = \frac{n}{2}(u_1 + u_n)\).

How is simple interest linked to arithmetic sequences?

Simple interest adds the same amount each period, so the balances form an arithmetic sequence with \(d\) = interest per period.

Exam tip: "find the first \(n\) for which \(S_n > k\)"

Solve \(S_n = k\) on the GDC, then round up to the next whole number, and check \(S_{n-1}\) and \(S_n\) with a table.